OR in a regular expression?
I have a text file with several thousand lines. I want to parse this file in a database and decided to write regexp. Here's part of the file:
blablabla checked=12 unchecked=1
blablabla unchecked=13
blablabla checked=14
As a result, I would like to get something like
(12,1) (0,13) (14,0)
Is it possible?
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5 answers
import re
s = """blablabla checked=12 unchecked=1
blablabla unchecked=13
blablabla checked=14"""
regex = re.compile(r"blablabla (?:(?:checked=)(\d+))? ?(?:(?:unchecked=)(\d+))?")
for line in s.splitlines():
print regex.match(line).groups()
This gives you lines (or None
if not found), but the idea should be clear.
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import re
lines = ["blablabla checked=12 unchecked=1", "blablabla unchecked=13"]
p1 = re.compile('checked=(\d)+\sunchecked=(\d)')
p2 = re.compile('checked=(\d)')
p3 = re.compile('unchecked=(\d)')
for line in lines:
m = p1.search(line)
if m:
print m.group(1), m.group(2)
else:
m = p2.search(line)
if m:
print m.group(1), "0"
else:
m = p2.search(line)
if m:
print "0", m.group(1)
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This is more general and reusable, I suppose:
import re
def tuple_producer(input_lines, attributes):
"""Extract specific attributes from lines 'blabla attribute=value …'"""
for line in input_lines:
line_attributes= {}
for match in re.finditer("(\w+)=(\d+)", line):
line_attributes[match.group(1)]= int(match.group(2)) # int cast
yield tuple(
line_attributes.get(attribute, 0) # int constant
for attribute in wanted_attributes)
>>> lines= """blablabla checked=12 unchecked=1
blablabla unchecked=13
blablabla checked=14""".split("\n")
>>> list(tuple_producer(lines, ("checked", "unchecked")))
[(12, 1), (0, 13), (14, 0)]
# and an irrelevant example
>>> list(tuple_producer(lines, ("checked", "inexistant")))
[(12, 0), (0, 0), (14, 0)]
Note the conversion to integer; if undesirable remove casting int
and also convert the 0
int constant to "0"
.
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