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How to pop up a tooltip at a specific position

I am trying to integrate a toolwindow in a Winforms application, it will be a tiny floating window to display the details of an item in a list. What I need is to put the window in a relative position to the control that launches the action, so here's what: the Location property gives me the relative position of the control from its container (main form in this case), so this is im workaround using :

    public void Show(kTextBox source)
    {

        Point absCoord = source.PointToScreen(source.Location);
        this.Location = this.PointToClient(absCoord);
        base.Show();

    }

Basically it is: get the absolute position of the control and set that position (previously converted to relative owner) to the tool window. I think it should work fine, but is missing to a certain extent and it depends on which control I am using. This confuses. Was there anyone? Thanks in advance.

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2 answers


What happens if you try the following:



public void Show(kTextBox source)
{
    Point control_origin = source.PointToScreen(new Point(0, 0));
    this.Location = new Point(control_origin.X, control_origin.Y);
    base.Show();
}
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   private void button1_Click(object sender, EventArgs e)
    {
        ToolStripDropDown popup = new ToolStripDropDown();
        popup.Margin = Padding.Empty;
        popup.Padding = Padding.Empty;
        ToolStripControlHost host = new ToolStripControlHost(frm);

        host.Margin = Padding.Empty;
        host.Padding = Padding.Empty;
        popup.Items.Add(host);
        popup.Show(button1, button1.Left - 10, button1.Top + (int)(button1.Height / 2));
    }

    Form2 frm = new Form2();
    private void Form1_Load(object sender, EventArgs e)
    {
        frm.TopLevel = false;
    }
}


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