How do I get a reference to an array in PHP 5?

Question

In php 5, all variable and objects are passed by reference, but I cannot get my codes to work

My codes:

$arrayA = array();

$array = $arrayA;
...
if(!in_array(thedata, $array)
    $array[] = thedata;
var_dump($arrayA);

The result is empty, am I missing something simple?

+2

Edward 09 Apr 10 at 15:02

4 answers

In PHP5, all objects are passed by reference (more or less), not all variables.

$array =& $arrayA;

+1

Simon 09 Apr 10:05 pm

Only objects are passed by reference. If you want to refer to simple types, you must use = & to assign:

php > $var1 = 'xxxxx';
php > $var2 =& $var1;
php > $var1 = 'yyyyy';
php > echo $var2;
yyyyy

+1

K. Norbert 09 Apr 10:06 pm

$array =& $arrayA;

0

Moak 09 Apr 10 at 15:04

Ivo Sabev · Accepted Answer · 2010-04-09T15:06:57+0000

<?php
    $arrayA = array();
    $arrayB =& $arrayA;
    $arrayB = array(1,2,3);
    var_dump($arrayA);

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