Create table if it doesn't exist

I wrote a code that should check the weather, there is a table named imei. $ addimei and if not, create it ...

$userdatabase = mysqli_connect('localhost', 'root', 'marina', 'imei');
...
$result = mysqli_query($userdatabase, "SELECT * FROM imei".$addimei."" );
if ( !$result ) { echo('creating table...'); /// if no such table, make one!

mysql_query ( $userdatabase,
'CREATE TABLE imei'.$addimei.'(
ID int NOT NULL AUTO_INCREMENT,
PRIMARY KEY(ID),

EVENT varchar(15),
TIME varchar(25),
FLD1 varchar(35),
FLD2 varchar(35),
IP varchar(25),
)' );
}

      

However, CREATE TABLE somehow doesn't work. Warning: mysql_query () expects parameter 1 to be a string, the object is listed in C: \ xampp \ xampp \ htdocs \ mobi \ mainmenu.php on line 564

Any idea what's wrong? Thanks!

+2


a source to share


1 answer


change:

http://pt.php.net/manual/en/function.mysql-query.php

mysql_query (
'CREATE TABLE imei'.$addimei.'(
ID int NOT NULL AUTO_INCREMENT PRIMARY KEY,

EVENT varchar(15),
TIME varchar(25),
FLD1 varchar(35),
FLD2 varchar(35),
IP varchar(25))', $userdatabase );

      



EDIT: Hi happened yesterday, sorry ... Your connection is mysqli, see EXAMPLE 2 on this page:

http://php.net/manual/en/mysqli.query.php

+2


a source







All Articles