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How to slice a list of objects into an object attribute association

I have a list of fixtures. Each lamp has a home club and country club attribute. I want to slice the list in association with his home club and away club. The sliced ​​list should consist of homeclub items and dropdown items.

The easiest way to do this is to slice the luminaire list first. Then create a new list of matching Home and Away Clubs. I wanted to know if we can get it one step.

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3 answers


It's not very clear what you are trying to do, but this code will take the first five fixtures and return a list of tuples, each containing the source and distant value of the corresponding object:

result = [(i.home, i.away) for i in fixtures[:5]]

This will split the two into two lists:



homes = [i.home for i in fixtures[:5]]
aways = [i.away for i in fixtures[:5]]

Or in one line:

homes, aways = [i.home for i in fixtures[:5]], [i.away for i in fixtures[:5]]
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Not really your answer, but (assuming [(home1, away1), (home2, away2), ...]

) it's about as easy as you get.



homes = [h for h,a in fixtures]
aways = [a for h,a in fixtures]
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Of course, with a little work:

def split(fixture):
    home, away = [], []
    for i, f in enumerate(fixture):
        if i >= 5:
            home.append(f.home)
            away.append(f.away)
    return home, away

Or:

home, away = zip(*itertools.imap(operator.attrgetter('home', 'away'),
    itertools.islice(fixture, 5, None)))
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