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How can I find the string position (index) from an XPath statement?

This question is close, but it is looking for an ordinal position. I am looking for the actual index position in a given source string.

Better explanation:

I have the following line

"<a>
    <b>zyx</b>
    <b>wvu</b>
    <b>tsr</b>
    <b>qpo</b>
</a>"

I am loading this string into a .NET XmlDocument object. Carriage return and cap can be a factor here.

Dim xmlSearchText As New XmlDocument()
xmlSearchText.LoadXml(SearchTextBox.Text)

Dim selectedNode As XmlNode = xmlSearchText.SelectSingleNode(txtSearch.Text)

The following XPath expression can be used to find the third node:

a/b[.='tsr']

However, I need to return line index 23, not ordinal position 3.

Possible? Impossible?

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2 answers


Does it give you what you want?

selectedNodenode = xmlSearchText.SelectSingleNode("a/b[.='tsr']");
selectedNode.ParentNode.OuterXml.IndexOf(selectedNode.OuterXml)


Will not tell you the index from the root, but it will give you the index from the parent node.

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Using XPathDocument instead of XmlDocument will allow you to access the IXmlLineInfo interface with line number and column position.

XPathDocument document = new XPathDocument("file.xml");
XPathNavigator navigator = document.CreateNavigator();
XPathNavigator node = navigator.Select("a/b[.='tsr']");
IXmlLineInfo info = ((IXmlLineInfo)node);
Console.WriteLine("Found at ({0},{1})",info.LineNumber,info.LinePosition);


If you really want the index of the character from the string, you can output it by counting the newlines and adding a column.

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