How do I remove the leaves of a binary tree?

I am trying to remove all the leaves. I know leaves have no children, this is what I still have.

 public void removeLeaves(BinaryTree n){  

    if (n.left == null && n.right == null){

        n = null;

    }

    if (n.left != null)

        removeLeaves(n.left);

    if (n.right != null)

        removeLeaves(n.right);

}

      

+2


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7 replies


It's much easier if you break it like this:

public void removeLeaves(BinaryTree n){
  if (n.left != null) {
    if (n.left.isLeaf()) {
      n.removeLeftChild();
    } else {
      removeLeaves(n.left);
    }
  }
  // repeat for right child
  // ...
}

      



isLeaf

, removeLeftChild

and removeRightChild

should be trivial to implement.

+5


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n = null;

won't help you, since n

- it's just a local variable of your function. Instead, you need to install n.left = null;

or n.right = null;

for the parent.



I won't give you a complete solution as it smells a lot like homework, but you can, for example, add a return value to your function to indicate whether the node in question is a leaf or not, do the appropriate steps in the parent (after the call removeLeaves

).

+5


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Instead of n = null, it should be:

if(n.parent != null)
  {
    if(n.parent.left == n)
    {
      n.parent.left = null;
    } 
    else if(n.parent.right == n)
    {
      n.parent.right == null);
    }
  }

      

+3


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Since Java passes references by values n = null;

, it just doesn't work. With this line, n pointed to the sheet and now points nothing. This way you are not actually removing it from the parent, you are just redirecting a dummy local link. For the solution, do what Matthew suggested.

+1


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 /* @author abhineet*/

public class DeleteLeafNodes {


    static class Node{
        int data;
        Node leftNode;
        Node rightNode;
        Node(int value){
            this.data = value;
            this.leftNode = null;
            this.rightNode = null;
        }
    }



    public static void main(String[] args) {

        Node root = new Node(1);
        Node lNode = new Node(2);
        lNode.leftNode = new Node(4);
        root.leftNode = lNode;
        Node rNode = new Node(3);
        rNode.rightNode = new Node(5);
        root.rightNode = rNode;
        printTree(root);
        deleteAllLeafNodes(root, null,0);
        System.out.println("After deleting leaf nodes::");
        printTree(root);

    }

    public static void deleteAllLeafNodes(Node root, Node parent, int direction){
        if(root != null && root.leftNode == null && root.rightNode == null){
            if(direction == 0){
                parent.leftNode = null;
            }else{
                parent.rightNode = null;
            }

        }
        if(root != null && (root.leftNode != null || root.rightNode != null)){
            deleteAllLeafNodes(root.leftNode, root, 0);
            deleteAllLeafNodes(root.rightNode, root, 1);
        }

    }
    public static void printTree(Node root){
        if(root != null){
            System.out.println(root.data);
            printTree(root.leftNode);
            printTree(root.rightNode);
        }
    }

}

      

0


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Here is a simple java method to remove leaf nodes from a binary tree

public BinaryTreeNode removeLeafNode(BinaryTreeNode root) {
    if (root == null)
        return null;
    else {
        if (root.getLeft() == null && root.getRight() == null) {     //if both left and right child are null
            root = null;                                             //delete it (by assigning null)
        } else {
            root.setLeft(removeLeafNode(root.getLeft()));            //set new left node 
            root.setRight(removeLeafNode(root.getRight()));          //set new right node   
        }
        return root;
    }

}

      

0


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This should work -

public boolean removeLeaves(Node n){  
    boolean isLeaf = false;
    if (n.left == null && n.right == null){
        return true;
        //n = null;
    }

    if (n!=null && n.left != null){

       isLeaf = removeLeaves(n.left);
       if(isLeaf) n.left=null; //remove left leaf
    }

    if (n!=null && n.right != null){

        isLeaf = removeLeaves(n.right);
        if(b) n.right=null; //remove right leaf
    }
    return false;

}

      

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