Postfix Expressions Assessment Program in Ruby

I tried to make a small script to evaluate post-fix expressions in Ruby.

def evaluate_post(expression)

    my_stack = Stack.new

    expression.each_char do |ch|        
    begin    
        # Get individual characters and try to convert it to integer
        y = Integer(ch)

        # If its an integer push it to the stack
        my_stack.push(ch)

    rescue    
        # If its not a number then it must be an operation
        # Pop the last two numbers
        num2 = my_stack.pop.to_i            
        num1 = my_stack.pop.to_i


        case ch
        when "+"   
            answer = num1 + num2        
        when "*"       
            answer = num1* num2    
        when "-"        
            answer = num1- num2     
        when "/"        
            answer = num1/ num2    
        end   

        # If the operation was other than + - * / then answer is nil
        if answer== nil
        my_stack.push(num2)
        my_stack.push(num1)
        else
        my_stack.push(answer)
        answer = nil
        end
    end
    end

    return my_stack.pop
end

      

  • I don't know of a better way to check if a character is an Integer without using this crude method or regular expressions. Do you have any suggestions?
  • Is there a way to abstract the cases. Does Ruby have an eval (num1 ch num2) function?
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2 answers


if you want to check if a string is an integer, Integer () is an elegant way to do it, because it ensures that your integer definition is ruby. if you prefer not to use this because it throws an exception, regexes work well - why avoid them? Also, note that in the integer case, you can just push y to your stack, not ch, and don't need calls to_i when it appears. as on the other question, the ruby ​​does have a rating.



y = Integer(ch) rescue nil   
if y  
  stack.push(y)  
else  
  num2, num1 = stack.pop(2)  
  a = eval "#{num2} #{ch} #{num1}" # see mehrdad comment for why not num1 ch num2  
  stack.push(a)  
end  

      

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I don’t know ruby, so I don’t answer your questions. However, there is an algorithmic problem. For addition, multiply the order of the operands doesn't matter, but for subtraction and division, you must subtract and divide the first operand by the second. The first is deeper in the stack. As a result, you should change these two lines:



num1 = my_stack.pop.to_i
num2 = my_stack.pop.to_i

      

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