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In C, does casting from char * to void * do something?

Please take a look at the below code snippet and tell me the difference?

int main()
{
struct sockaddr_in serv_addr, cli_addr;
/* Initialize socket structure */
    bzero((char *) &serv_addr, sizeof(serv_addr));
}

Now, what if I do something like this without styling (char *)

, then also I feel like it will do the same? Can anyone clarify?

/* Initialize socket structure */
bzero( &serv_addr, sizeof(serv_addr));
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2 answers


Since the first parameter is void *

, you only need to execute it in C ++.

In C, this is optional, since 1void *

was introduced exactly so that you didn't have to cast it into a pointer or from other pointers 2 (Similar with and other s- related functions )malloc()

void *



  • The C89.
  • Any non-functional pointers.
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Casting is not required because it bzero()

takes void*

as the first argument, and AnyType*

can be implicitly converted to void*

.



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