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Syntax for writing a loop inside a batch file

I am trying to write a small batch file for a task that I do regularly. I have never used it before for

and this is the first time I try this. This is what I ended up with:

for /f %i in  ('ct find . -ver lbtype(%1) -print') do ct lsvt -g %i

Basically it tries to find all files with the specified cleracase tag and then display the version tree of those files. The problem is %1

. But when I try to run this sometime it gives me an error saying -print )

not expected or ever else it just prints this command on the command line. I guess this is confusing between several paradelts. Any hints how I solve this?

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1 answer


Try to specify the command you are running in for

:

for /f %i in  ('"ct find . -ver lbtype(%1) -print"') do ct lsvt -g %i

This worked for the same command as mine, with arguments with parens.



Also, as you probably know, you need to double characters '%'

for the variable for

if you put the command in a batch file instead of running it on the command line:

for /f %%i in  ('"ct find . -ver lbtype(%1) -print"') do ct lsvt -g %%i
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