Is IMUL AX really?
I spent the last hour of googling trying to figure out if IMUL AX is indeed the correct command in 80x86 assembler. Sorry for not trying, I just don't have the tools on the PC I'm currently using.
All I need is just a quick yes / no answer. Thanks!
jpou
Update: Checked and verified today. Works as expected.
-R
AX=0002 BX=0000 CX=20CD DX=0000 SP=FFEE BP=0000 SI=0000 DI=0000
DS=0B02 ES=9FFF SS=0B02 CS=0B02 IP=0102 NV UP EI PL NZ NA PO NC
0B02:0102 F7E0 MUL A
-X
-T
AX=0004 BX=0000 CX=20CD DX=0000 SP=FFEE BP=0000 SI=0000 DI=0000
DS=0B02 ES=9FFF SS=0B02 CS=0B02 IP=0104 NV UP EI PL NZ NA PO NC
0B02:0104 FE7405 PUSH [SI+05] DS:0005=9A
+1
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2 answers
Sorry for not trying, I just don't have the tools on the PC I'm currently using.
From the command line:
Microsoft Windows [Version 6.0.6001]
Copyright (c) 2006 Microsoft Corporation. All rights reserved.
C:\Windows\system32>debug
-a
17CC:0100 imul ax
17CC:0102
-u
17CC:0100 F7E8 IMUL AX
17CC:0102 0000 ADD [BX+SI],AL
-q
By using the debug command, one can verify that "imul ax" will build (and therefore a valid command in 80x86 assembler).
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